Exercices on rationality

[Manjushri]

Racket = Ball + 10

ball+racket =11

2 balls = 1

ball 0.5 lol

and second, we cant know. 

[Harikrishnan]

Price of racket is 10 more than ball and total cost of two item is 11. Lets check options if ball cost two then total will be more than 12 since racket cost 10+. If option is 1 ie price of ball is 1 then total cost will be 10+(more )+1 which gives total sum to be 11more.  So the answer is .5.  10 more than .5 is 10.5.?

[Nahm]

@Shin

A.05.   How much they are sold for together is inconsequential / unrelative. 

B. Yes. It’s yes wether Lea is married or not. It’s a matter of which ‘looker’.

 

 

[Shin]

16 minutes ago, Harikrishnan said:

Price of racket is 10 more than ball and total cost of two item is 11. Lets check options if ball cost two then total will be more than 12 since racket cost 10+. If option is 1 ie price of ball is 1 then total cost will be 10+(more )+1 which gives total sum to be 11more.  So the answer is .5.  10 more than .5 is 10.5.?

Seems SO easy when you have the answer, otherwise the mind tends to think he can't be wrong over such a simple task …
So he never check the obvious and stay on its position.
That reminds me something hummmmmmmm   

 

8 minutes ago, Nahm said:

@Shin

A.05.   How much they are sold for together is inconsequential / unrelative. 

B. Yes. It’s yes wether Lea is married or not. It’s a matter of which ‘looker’.

If she is married she is watching someone non married.
If she is not married, the person on the right is.

In both case someone that is married watch someone that isn't.

Edited November 25, 2018 by Shin

[Nahm]

12 minutes ago, Shin said:

Seems SO easy when you have the answer

 

Or when you already know every word is bs. It makes it much easier to identify and discard what is not even relative (over thinking). 

 

[Outer]

31 minutes ago, Shin said:

If she is married she is watching someone non married.
If she is not married, the person on the right is.

In both case someone that is married watch someone that isn't.

Lel I feel retarded now, that's genius

[ajasatya]

oh c'mon. those are pretty simple ones...

1. a system of linear equations: { R + B = 11; R - B = 10 => { R = 10.5; B = 0.5
2. suppose lea is married => lea (married) watches richard (not married) => yes
   suppose lea is not married => jon (married) watches lea (not married) => yes
   the answer is yes regardless of lea's maritial status

[ajasatya]

here, a more exciting exercise...

bob asks ana if she's wearing underwear. ana answers:

Quote

i am using underwear if, and only if, i am speaking the truth.

is ana using underwear?